Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

APPENDIX D - Trigonometry - D Exercises - Page A 32: 24

Answer

$sin\frac{4\pi}{3}=-\frac{\sqrt 3}{2}$ $cos\frac{4\pi}{3}=-\frac{1}{2}$ $tan\frac{4\pi}{3}=\sqrt 3$, $csc\frac{4\pi}{3}=-\frac{2\sqrt 3}{3}$, $sec\frac{4\pi}{3}=-2$, $cot\frac{4\pi}{3}=\frac{\sqrt 3}{3}$

Work Step by Step

The trigonometric ratios and their inverse trigonometric ratios are given as follows: $sin\frac{4\pi}{3}=-sin\frac{\pi}{3}=-\frac{\sqrt 3}{2}$ $csc\frac{4\pi}{3}=\frac{1}{sin\frac{4\pi}{3}}=-\frac{2\sqrt 3}{3}$ $cos\frac{4\pi}{3}=-cos\frac{\pi}{3}=-\frac{1}{2}$ $sec\frac{4\pi}{3}=\frac{1}{cos\frac{4\pi}{3}}=-2$ $tan\frac{4\pi}{3}=tan\frac{\pi}{3}=\sqrt 3$ $cot\frac{4\pi}{3}=\frac{1}{tan\frac{4\pi}{3}}=\frac{\sqrt 3}{3}$
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