Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

APPENDIX B - Coordinate Geometry and Lines - B Exercises: 3

Answer

$\sqrt {74} $

Work Step by Step

To find the distance between $(6,-2)$ and $(-1,3)$, we use the distance formula: $d=\sqrt {(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$. We plug in the given $x$ and $y$ values: $d=\sqrt {(-1-6)^{2}+(3-(-2))^{2}}$. We then simplify to arrive at the answer: $d=\sqrt {(-7)^{2}+5^{2}}=\sqrt {74} $.
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