Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

APPENDIX B - Coordinate Geometry and Lines - B Exercises: 2

Answer

$ 2\sqrt {29}$

Work Step by Step

To find the distance between $(1,-3)$ and $(5,7)$, we use the distance formula: $d=\sqrt {(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$. We plug in the given $x$ and $y$ values: $d=\sqrt {(5-1)^{2}+(7-(-3))^{2}}$. We then simplify to arrive at the answer: $d=\sqrt {4^{2}+10^{2}}=\sqrt {116} = 2\sqrt {29}$.
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