Answer
$\frac{a-c}{b}\leq x\lt \frac{2a-c}{b}$
Work Step by Step
Solve the inequality $a\leq bx+c\lt 2a$ for $x$, assuming a, b, and c are positive constants.
Thus,
Subtract $c$:
$a-c\leq bx\lt 2a-c$
Divide $b$:
$\frac{a-c}{b}\leq x\lt \frac{2a-c}{b}$
Hence, $\frac{a-c}{b}\leq x\lt \frac{2a-c}{b}$
