Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

APPENDIX A - Numbers, Inequalities, and Absolute Values - A Exercises: 57

Answer

$x\geq c(\frac{a+b}{ab})$

Work Step by Step

Given: $a(bx-c)\geq bc$ The solution set for $x$ can be calculated as follows: $bx\geq \frac{bc}{a}+c$ $x\geq c(\frac{1}{a}+\frac{1}{b})$ $x\geq c(\frac{a+b}{ab})$ Hence, the solution set is $x\geq c(\frac{a+b}{ab})$.
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