Answer
$x\geq c(\frac{a+b}{ab})$
Work Step by Step
Given: $a(bx-c)\geq bc$
The solution set for $x$ can be calculated as follows:
$bx\geq \frac{bc}{a}+c$
$x\geq c(\frac{1}{a}+\frac{1}{b})$
$x\geq c(\frac{a+b}{ab})$
Hence, the solution set is $x\geq c(\frac{a+b}{ab})$.