Answer
$$x{\cos ^{ - 1}}x - \sqrt {1 - {x^2}} + C$$
Work Step by Step
$$\eqalign{
& \int {{{\cos }^{ - 1}}x} dx \cr
& {\text{A matching integral in a table of integrals at the end of the book is the }} \cr
& {\text{formula }}17 \cr
& \int {{{\cos }^{ - 1}}x} dx = x{\cos ^{ - 1}}x - \sqrt {1 - {x^2}} + C \cr} $$