Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 7 - Integration Techniques - 7.4 Trigonometric Substitutions - 7.4 Exercises - Page 537: 2

Answer

$$x = 6\tan \theta $$

Work Step by Step

$$\eqalign{ & {\text{The integral }}\sqrt {{x^2} + 36} {\text{ contains }}{x^2} + {a^2},{\text{ then the change of }} \cr & {\text{variables suggested is}}:\,\,x = a\tan \theta \cr & {\text{Let }}a = 6,{\text{ then}} \cr & x = 6\tan \theta \cr} $$
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