Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 7 - Integration Techniques - 7.1 Basic Approaches - 7.1 Exercises - Page 515: 41

Answer

\[\begin{align} & \text{a}\text{. False}\text{.} \\ & \text{b}\text{. False}\text{.} \\ & \text{c}\text{. False}\text{.} \\ & \text{d}\text{. False}\text{.} \\ \end{align}\]

Work Step by Step

\[\begin{align} & \text{a}\text{. }\int{\frac{3}{{{x}^{2}}+4}=\int{\frac{3}{{{x}^{2}}}dx}+\int{\frac{3}{4}}dx} \\ & \text{The statement is false, because we cannot add the } \\ & \text{denominators of a rational functions}\text{.} \\ & \\ & \text{b}\text{. }\int{\frac{{{x}^{3}}+2}{3{{x}^{4}}+x}}dx \\ & \text{The statement is false, because this is not an improper rational} \\ & \text{function, the degree of the denominator is greater than the} \\ & \text{numerator}\text{.} \\ & \\ & \text{c}\text{. }\int{\frac{dx}{\sin x+1}=\ln \left| \sin x+1 \right|+C} \\ & \text{The statement is false, because the numerator does not contain} \\ & \text{the derivative the denominator, then the rule does not apply}\text{.} \\ & \\ & \text{d}\text{. }\int{\frac{dx}{{{e}^{x}}}=\ln {{e}^{x}}+C} \\ & \text{The statement is false, }\ln {{e}^{x}}=x\text{ and }\int{\frac{dx}{{{e}^{x}}}\text{ is not }\int{dx}}. \\ \end{align}\]
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