Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 6 - Applications of Integration - 6.6 Surface Area - 6.6 Exercises - Page 458: 30

Answer

The surface of cone is not equal to $\dfrac{1}{3}$ rd of cylinder.

Work Step by Step

The surface area of cone is equal to $S(cone)=\pi r \sqrt {r^2+h^2}$ and the surface area of cylinder is equal to $S(cylinder)=2 \pi r h$ Now, $\dfrac{S(cone)}{S(cylinder)}=\dfrac{\pi r \sqrt {r^2+h^2}}{2 \pi r h}$ This implies that $\dfrac{S(cone)}{S(cylinder)}=\dfrac{1}{2} \sqrt {1+\dfrac{r^2}{h^2}}$ We conclude that the surface of cone is not equal to $\dfrac{1}{3}$ rd of cylinder.
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