Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 6 - Applications of Integration - 6.3 Volume by Slicing - 6.3 Exercises - Page 431: 22

Answer

$\dfrac{500 \pi }{3} \ unit \ cube$

Work Step by Step

Since, the vertical slices solid are circular discs , so we will use the disk method to compute the volume of revolution of the curve. The volume of revolution of the curve can be expressed as: $V=\pi \int_p^q [f(x)]^2 dx\\=\pi \int_{-5}^{5} [\sqrt {25-x^2}]^{2} \ dx \\= \pi \int_{-5}^{5} (25-x^2) \ dx \\=2 \pi [25-x^2] \\=2 \pi [125-\dfrac{125}{3}]\\=\dfrac{500 \pi }{3} \ unit \ cube$
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