Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 6 - Applications of Integration - 6.10 Hyperbolic Functions - 6.10 Exercises - Page 502: 3

Answer

$${\text{co}}{{\text{s}}^2}t - {\sin ^2}t = 1$$

Work Step by Step

$$\eqalign{ & {\text{The fundamental identity for hyperbolic functions is:}} \cr & {\text{ co}}{{\text{s}}^2}t - {\sin ^2}t = 1 \cr & {\text{See the page 492 in this section}}{\text{.}} \cr} $$
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