Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 5 - Integration - 5.4 Working with Integrals - 5.4 Exercises - Page 382: 42

Answer

0

Work Step by Step

We know that tan(-x)= -tan x. That is, tan x is an odd function. Also, there is symmetry in the interval. So we use theorem 5.4 to get $\int^{\frac{\pi}{4}}_{\frac{-\pi}{4}}tanxdx= 0$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.