Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 5 - Integration - 5.4 Working with Integrals - 5.4 Exercises - Page 381: 12

Answer

$$0$$

Work Step by Step

$$\eqalign{ & \int_{ - \pi /2}^{\pi /2} {5\sin xdx} \cr & {\text{ the function }}\sin x{\text{ is odd}} \cr & {\text{Use the theorem 5}}{\text{.4}} \cr & {\text{If }}f\left( x \right){\text{ is odd}}{\text{, }}\int_{ - a}^a {f\left( x \right)dx} = 0 \cr & then \cr & 5\int_{ - \pi /2}^{\pi /2} {\sin xdx} = 5\left( 0 \right) \cr & 5\int_{ - \pi /2}^{\pi /2} {\sin xdx} = 0 \cr} $$
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