Answer
$-1$
Work Step by Step
We have
$$
\int_{0}^{3\pi/2} x \sin x d x=R_1+R_2-R_3=1+\pi-1-\pi-1=-1.
$$
Calculus: Early Transcendentals (2nd Edition)
by Briggs, Bill L.; Cochran, Lyle; Gillett, Bernard
Published by
Pearson
ISBN 10:
0321947347
ISBN 13:
978-0-32194-734-5
Chapter 5 - Integration - 5.2 Definite Integrals - 5.2 Exercises - Page 359: 38
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
