Answer
\[\begin{align}
& \text{Absolute maximum: }\left( -\frac{3\pi }{4},4 \right)\text{ and }\left( \frac{\pi }{4},4 \right) \\
& \text{Absolute minimum: }\left( -\frac{\pi }{4},2 \right)\text{ and }\left( \frac{3\pi }{4},2 \right)\text{ } \\
\end{align}\]
Work Step by Step
\[\begin{align}
& f\left( x \right)=\sin 2x+3\text{ on }\left[ -\pi ,\pi \right] \\
& \text{Differentiate} \\
& f'\left( x \right)=\sin 2x+3 \\
& f'\left( x \right)=\cos 2x\left( 2 \right)+0 \\
& f'\left( x \right)=2\cos 2x \\
& \text{Calculate the critial points, set }f'\left( x \right)=0 \\
& 2\cos 2x=0 \\
& \cos 2x=0 \\
& \text{For the interval }\left[ -\pi ,\pi \right]\text{ }\cos 2x=0,\text{ when } \\
& x=\pm \frac{\pi }{4}\text{, }\pm \frac{3\pi }{4}\text{ } \\
& \text{Therefore} \\
& \text{We have the critical points} \\
& x=\pm \frac{\pi }{4}\text{, }\pm \frac{3\pi }{4}\text{ } \\
& \text{Evaluating }f\text{ at each of these points, we have} \\
& f\left( -\pi \right)=\sin 2\left( -\pi \right)+3=3 \\
& f\left( -\frac{3\pi }{4} \right)=\sin 2\left( -\frac{3\pi }{4} \right)+3=4 \\
& f\left( -\frac{\pi }{4} \right)=\sin 2\left( -\frac{\pi }{4} \right)+3=2 \\
& f\left( \frac{\pi }{4} \right)=\sin 2\left( \frac{\pi }{4} \right)+3=4 \\
& f\left( -\frac{3\pi }{4} \right)=\sin 2\left( -\frac{3\pi }{4} \right)+3=2 \\
& f\left( \pi \right)=\sin 2\left( \pi \right)+3=3 \\
& \text{The largest of those function values are:} \\
& f\left( -\frac{3\pi }{4} \right)=4\text{ and }f\left( \frac{\pi }{4} \right)=4 \\
& \text{Which are absolute }\left( \text{and local} \right)\text{ maximum on }\left[ -\pi ,\pi \right] \\
& \text{The smallest of those function values are:} \\
& f\left( -\frac{\pi }{4} \right)=2\text{ and }f\left( \frac{3\pi }{4} \right)=2 \\
& \text{Which are absolute }\left( \text{and local} \right)\text{ minimum on }\left[ -\pi ,\pi \right] \\
& \\
& \text{Absolute maximum: }\left( -\frac{3\pi }{4},4 \right)\text{ and }\left( \frac{\pi }{4},4 \right) \\
& \text{Absolute minimum: }\left( -\frac{\pi }{4},2 \right)\text{ and }\left( \frac{3\pi }{4},2 \right) \\
\end{align}\]