Answer
$H(y) = ln(y)+c$
Work Step by Step
$h(y)=y^{-1}$
$\int h(y)dy = \int y^{-1}$
$H(y) = ln(y)+c$
Calculus: Early Transcendentals (2nd Edition)
by Briggs, Bill L.; Cochran, Lyle; Gillett, Bernard
Published by
Pearson
ISBN 10:
0321947347
ISBN 13:
978-0-32194-734-5
Chapter 4 - Applications of the Derivative - 4.9 Antiderivatives - 4.9 Exercises - Page 327: 20
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