Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 4 - Applications of the Derivative - 4.9 Antiderivatives - 4.9 Exercises - Page 327: 17

Answer

$F(y) = $ $y^{-2} +c$

Work Step by Step

$f(y)=\frac{-2}{y^3}$ $f(y)= -2y^{-3}$ $\int f(y)dy = -2\int y^{-3}$ $F(y)= -2\int \frac{y^{-2}}{-2}$ $F(y) = $ $y^{-2} +c$
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