Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 4 - Applications of the Derivative - 4.9 Antiderivatives - 4.9 Exercises: 13

Answer

$F(x)=-\frac{1}{2}cos 2x +c$

Work Step by Step

$f(x)=sin2x$ $\int f(x)dx = \int sin 2x$ $F(x)= \frac{1}{2}\int(sin2x)$ $F(x)=-\frac{1}{2}cos 2x +c$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.