Answer
See the graph.
Work Step by Step
$f(x) = tan(x)$ on the interval $(-\frac{\pi}{2},\frac{\pi}{2})$ is continuous, but has neither an absolute maximum nor an absolute minimum value on $(-\frac{\pi}{2},\frac{\pi}{2})$.
Calculus: Early Transcendentals (2nd Edition)
by Briggs, Bill L.; Cochran, Lyle; Gillett, Bernard
Published by
Pearson
ISBN 10:
0321947347
ISBN 13:
978-0-32194-734-5
Chapter 4 - Applications of the Derivative - 4.1 Maxima and Minima - 4.1 Exercises - Page 242: 4
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