## Calculus: Early Transcendentals (2nd Edition)

$g(x)$; $x$ The derivative of $f(g(x))$ equals $f'$ evaluated at $\boxed{g(x)}$ multiplied by $g'$ evaluated at $\boxed x$
According to Theorem 3.14: $\frac{d}{dx}[f(g(x))]=f'(g(x)) \times g'(x)$