## Calculus: Early Transcendentals (2nd Edition)

To calculate $h'(1)$, we need to know $f'(3)$
According to Theorem 3.14: $\frac{d}{dx}[f(g(1))] = h'(1)= f'(g(1)) \times g'(1)$ We know that $g(1) = 3$ and $g'(1) = 5$, so when we plug in these values into the equation, we get: $h'(1) = f'(3) \times 5$ Thus, we need to know the value of $f'(3)$ to solve for $h'(1)$