Answer
$s'(t)=2t^{-1/2}-t^{3}+1$
Work Step by Step
$s(t)=4\sqrt t-(1/4)t^{4}+t+1$
$s(t)=4t^{1/2}-(1/4)t^{4}+t+1$
$s'(t)=(4)(1/2)t^{1/2-1}-(1/4)(4)t^{4-1}+1t^{1-1}+0$
$s'(t)=2t^{-1/2}-1t^{3}+1t^{0}$
$s'(t)=2t^{-1/2}-t^{3}+1$
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