Answer
$f'(s)=\dfrac{1}{8\sqrt{s}}$
Work Step by Step
Rewrite the function:
$f(s)=\dfrac{1}{4}s^{1/2}$
Apply the power rule:
$f'(s) =\dfrac{1}{4}(\dfrac{1}{2})s^{1/2-1}$
$f'(s)=\dfrac{1}{8}s^{-1/2}$
$f'(s)=\dfrac{1}{8\sqrt{s}}$
Calculus: Early Transcendentals (2nd Edition)
by Briggs, Bill L.; Cochran, Lyle; Gillett, Bernard
Published by
Pearson
ISBN 10:
0321947347
ISBN 13:
978-0-32194-734-5
Chapter 3 - Derivatives - 3.3 Rules of Differentiation - 3.3 Exercises - Page 151: 18
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