Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 3 - Derivatives - 3.3 Rules of Differentiation - 3.3 Exercises: 17

Answer

$g'(t) = 200t$

Work Step by Step

$g(t) =100t^2$ $g'(t) = 100\times (t^2)'$ $(t^2)'=2t^1 = 2t$ Therefore $g'(t) = 100 \times (t^2)'= 100\times 2t = 200t$
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