Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 3 - Derivatives - 3.3 Rules of Differentiation - 3.3 Exercises: 15

Answer

$p'(x) = 8$

Work Step by Step

$p(x) = 8x$ $p'(x) = 8\times (x)'$ $(x)'=1x^0=1$ Therefore $p'(x) = 8 \times (x)'= 8\times1 = 8$
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