Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 2 - Limits - 2.7 Precise Definitions of Limits - 2.7 Exercises - Page 120: 5

Answer

$$\eqalign{ & {\text{The limit of }}f\left( x \right){\text{as }}x{\text{ approaches }}a{\text{ is }}L,{\text{ written}} \cr & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\mathop {\lim }\limits_{x \to a} f\left( x \right) = L \cr & {\text{if for }}any\,\varepsilon > 0{\text{ there is a corresponding number }}\delta {\text{ > 0 such that}} \cr & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\left| {f\left( x \right) - L} \right| < \varepsilon {\text{ whenever }}0 < \left| {x - a} \right| < \delta \cr} $$

Work Step by Step

$$\eqalign{ & {\text{The precise definition of }}\mathop {\lim }\limits_{x \to a} f\left( x \right) = L{\text{ is:}} \cr & {\text{The limit of }}f\left( x \right){\text{as }}x{\text{ approaches }}a{\text{ is }}L,{\text{ written}} \cr & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\mathop {\lim }\limits_{x \to a} f\left( x \right) = L \cr & {\text{if for }}any\,\varepsilon > 0{\text{ there is a corresponding number }}\delta {\text{ > 0 such that}} \cr & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\left| {f\left( x \right) - L} \right| < \varepsilon {\text{ whenever }}0 < \left| {x - a} \right| < \delta \cr} $$
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