Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 2 - Limits - 2.7 Precise Definitions of Limits - 2.7 Exercises - Page 120: 3

Answer

$${\bf{c}}.\,\left( {3,8} \right)$$

Work Step by Step

$$\eqalign{ & {\text{Using the midpoint rule for all points}} \cr & {\bf{a}}.\,\left( {1,9} \right) \cr & \frac{{1 + 9}}{2} = 5 \cr & {\bf{b}}.\,\left( {4,6} \right) \cr & \frac{{4 + 6}}{2} = 5 \cr & {\bf{c}}.\,\left( {3,8} \right) \cr & \frac{{3 + 8}}{2} = \frac{{11}}{2} = 5.5 \cr & {\bf{d}}.\,\left( {4.5,5.5} \right) \cr & \frac{{4.5 + 5.5}}{2} = 5 \cr & {\text{The answer is }}{\bf{c}}.\,\left( {3,8} \right) \cr} $$
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