Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 2 - Limits - 2.6 Continuity - 2.6 Exercises - Page 108: 19

Answer

Not continuous

Work Step by Step

We are given the function: $f(x)=\dfrac{5x-2}{x^2-9x+20}$ We use the continuity checklist to determine if $f$ is continuous in $a=4$: 1) Rewrite $f(x)$: $f(x)=\dfrac{5x-2}{x^2-4x-5x+20}=\dfrac{5x-2}{x(x-4)-5(x-4)}$ $=\dfrac{5x-2}{(x-4)(x-5)}$ $a=4$ is a zero of the denominator, therefore $f$ is not defined for $a=4$. As the condition 1 is not satisfied, the function is not continuous in $a=4$.
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