Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 2 - Limits - 2.5 Limits at Infinity - 2.5 Exercises - Page 97: 70

Answer

$${\text{0}}$$

Work Step by Step

$$\eqalign{ & {\text{Let }}p\left( t \right) = \frac{{2500}}{{t + 1}} \cr & {\text{Calculate }}\mathop {\lim }\limits_{t \to \infty } p\left( t \right) \cr & {\text{ }}\mathop {\lim }\limits_{t \to \infty } p\left( t \right) = \mathop {\lim }\limits_{t \to \infty } \frac{{2500}}{{t + 1}} \cr & {\text{Evaluate using limit properties}} \cr & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = 2500\overbrace {\mathop {\lim }\limits_{t \to \infty } \frac{1}{{t + 1}}}^{{\text{approaches to 0}}} \cr & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = 2500\left( 0 \right) \cr & {\text{ }}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = 0 \cr & {\text{Therefore}}{\text{, }} \cr & {\text{The steady state exits}} \cr & {\text{The steady - state value is 0}} \cr} $$
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