Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 2 - Limits - 2.5 Limits at Infinity - 2.5 Exercises: 22

Answer

$0$

Work Step by Step

$$\lim _{x\rightarrow -\infty }2x^{-8}=\lim _{x\rightarrow -\infty }\dfrac {2}{x^{8}}=0$$
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