Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 2 - Limits - 2.5 Limits at Infinity - 2.5 Exercises - Page 96: 12

Answer

$4$

Work Step by Step

$\lim _{x\rightarrow \infty }\dfrac {3+2x+4x^{2}}{x^{2}}=\dfrac {3}{x^{2}}+\dfrac {2}{x}+4=0+0+4=4$
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