Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 2 - Limits - 2.4 Infinite Limits - 2.4 Exercises - Page 88: 51

Answer

$x=0$

Work Step by Step

We are given the function: $f(x)=\dfrac{1}{\sqrt x\sec x}$ We should compute $\lim\limits_{x \to a} f(x)=\lim\limits_{x \to a}\dfrac{1}{\sqrt x\sec x}=\lim\limits_{x \to a}\dfrac{1}{\sqrt x\cdot\dfrac{1}{\cos x}}=\lim\limits_{x \to a}\dfrac{\cos x}{\sqrt x}$ Therefore $f(x)$ has one vertical asymptote in $x=0$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.