Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 2 - Limits - 2.4 Infinite Limits - 2.4 Exercises - Page 88: 50

Answer

$s=0$

Work Step by Step

We are given the function: $q(s)=\dfrac{\pi}{s-\sin s}$ We should compute $\lim\limits_{s \to a} q(s)=\lim\limits_{s \to a}\dfrac{\pi}{s-\sin s}$ The function $q(s)$ is undefined for $s-\sin s=0$. $s=\sin s$ $\sin s\in[-1,1]$ On the interval $[-1,1]$, $y=s$ is ascending, while $y=\sin s$ is also ascending. They intersect in $s=0$. As they are bot ascending functions, $s=0$ is the only intersection. Therefore $q(s)$ has one vertical asymptote in $s=0$.
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