Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 11 - Vectors and Vector-Valued Functions - 11.6 Calculus of Vector-Valued Functions - 11.6 Exercises: 47

Answer

$\int\textbf{r}(t) dt = \langle \frac{1}{5}t^5-\frac{3}{2}t^2, t^2-t, 10t\rangle + C$

Work Step by Step

To find the indefinite integral, compute the integral of each component. $\int\textbf{r}(t) dt = \langle \int t^4-3t\ dt,\int 2t-1\ dt,\int 10\ dt\rangle = \langle \frac{1}{5}t^5-\frac{3}{2}t^2, t^2-t, 10t\rangle + C$
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