Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 11 - Vectors and Vector-Valued Functions - 11.5 Lines and Curves in Space - 11.5 Exercises - Page 806: 26

Answer

$\textbf{r} = \langle 1,0,1\rangle + t\langle-1,-2,0 \rangle$

Work Step by Step

Equation of a Line: $\textbf{r} = \textbf{r}_0 + t\textbf{v}$ Given points $(1,0,1)$ and $(0,-2,1)$ Use one of the points as $\textbf{r}_0$ $\textbf{r}_0 = \langle 1,0,1\rangle$ Given the two points, we can find $\textbf{v}$: $\textbf{v} = \langle0-1, -2-0, 1-1\rangle = \langle -1,-2,0\rangle$ $\textbf{r} = \langle 1,0,1\rangle + t\langle-1,-2,0 \rangle$
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