Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 11 - Vectors and Vector-Valued Functions - 11.4 Cross Products - 11.4 Exercises - Page 797: 38

Answer

\[\left\langle -14,-14,14 \right\rangle \]

Work Step by Step

\[\begin{align} & \text{Let }\mathbf{u}=\left\langle 6,-2,4 \right\rangle \text{ and }\mathbf{v}=\left\langle 1,2,3 \right\rangle \\ & \text{A vector orthogonal to }\mathbf{u}\text{ and }\mathbf{v}\text{ is parallel to }\mathbf{u}\times \mathbf{v}\text{. One such } \\ & \text{orthogonal vector is} \\ & \mathbf{u}\times \mathbf{v}=\left| \begin{matrix} \mathbf{i} & \mathbf{j} & \mathbf{k} \\ 6 & -2 & 4 \\ 1 & 2 & 3 \\ \end{matrix} \right| \\ & \mathbf{u}\times \mathbf{v}=\left| \begin{matrix} -2 & 4 \\ 2 & 3 \\ \end{matrix} \right|\mathbf{i}-\left| \begin{matrix} 6 & 4 \\ 1 & 3 \\ \end{matrix} \right|\mathbf{j}+\left| \begin{matrix} 6 & -2 \\ 1 & 2 \\ \end{matrix} \right|\mathbf{k} \\ & \mathbf{u}\times \mathbf{v}=\left( -6-8 \right)\mathbf{i}-\left( 18-4 \right)\mathbf{j}+\left( 12+2 \right)\mathbf{k} \\ & \mathbf{u}\times \mathbf{v}=-14\mathbf{i}-14\mathbf{j}+14\mathbf{k} \\ & \mathbf{u}\times \mathbf{v}=\left\langle -14,-14,14 \right\rangle \\ \end{align}\]
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