Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 11 - Vectors and Vector-Valued Functions - 11.4 Cross Products - 11.4 Exercises - Page 797: 32

Answer

\[{\mathbf{u}} \times {\mathbf{v}} = \left\langle { - 8,9,10} \right\rangle {\text{ and }}{\mathbf{u}} \times {\mathbf{v}} = \left\langle {8, - 9, - 10} \right\rangle \]

Work Step by Step

\[\begin{gathered} {\mathbf{u}} = \left\langle {3, - 4,6} \right\rangle ,\,\,\,{\mathbf{v}} = \left\langle {1,2, - 1} \right\rangle \hfill \\ \hfill \\ {\text{Calculate }}{\mathbf{u}} \times {\mathbf{v}} \hfill \\ {\mathbf{u}} \times {\mathbf{v}} = \left| {\begin{array}{*{20}{c}} {\mathbf{i}}&{\mathbf{j}}&{\mathbf{k}} \\ 3&{ - 4}&6 \\ 1&2&{ - 1} \end{array}} \right| \hfill \\ {\mathbf{u}} \times {\mathbf{v}} = \left| {\begin{array}{*{20}{c}} { - 4}&6 \\ 2&{ - 1} \end{array}} \right|{\mathbf{i}} - \left| {\begin{array}{*{20}{c}} 3&6 \\ 1&{ - 1} \end{array}} \right|{\mathbf{j}} + \left| {\begin{array}{*{20}{c}} 3&{ - 4} \\ 1&2 \end{array}} \right|{\mathbf{k}} \hfill \\ {\mathbf{u}} \times {\mathbf{v}} = \left( {4 - 12} \right){\mathbf{i}} - \left( { - 3 - 6} \right){\mathbf{j}} + \left( {6 + 4} \right){\mathbf{k}} \hfill \\ {\mathbf{u}} \times {\mathbf{v}} = - 8{\mathbf{i}} + 9{\mathbf{j}} + 10{\mathbf{k}} \hfill \\ {\mathbf{u}} \times {\mathbf{v}} = \left\langle { - 8,9,10} \right\rangle \hfill \\ and \hfill \\ {\mathbf{v}} \times {\mathbf{u}} = - {\mathbf{u}} \times {\mathbf{v}} \hfill \\ {\mathbf{v}} \times {\mathbf{u}} = - \left\langle { - 8,9,10} \right\rangle \hfill \\ {\mathbf{v}} \times {\mathbf{u}} = \left\langle {8, - 9, - 10} \right\rangle \hfill \\ \end{gathered} \]
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