Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 11 - Vectors and Vector-Valued Functions - 11.2 Vectors in Three Dimensions - 11.2 Exercises - Page 778: 34

Answer

$$\eqalign{ & {\text{All the points on or inside the sphere centered at }}\left( {0,7,0} \right) \cr & {\text{with radius 6}} \cr} $$

Work Step by Step

$$\eqalign{ & {x^2} + {y^2} - 14y + {z^2} \leqslant - 13 \cr & {\text{Group terms}} \cr & {x^2} + \left( {{y^2} - 14y} \right) + {z^2} \leqslant - 13 \cr & {\text{Complete the square}} \cr & {x^2} + \left( {{y^2} - 14y + 49} \right) + {z^2} \leqslant - 13 + 49 \cr & {x^2} + {\left( {y - 7} \right)^2} + {z^2} \leqslant {\left( 6 \right)^2} \cr & {\text{The equation of the form }}{\left( {x - a} \right)^2} + {\left( {y - b} \right)^2} + {\left( {z - c} \right)^2} = {r^2} \cr & {\text{Represents a sphere centered at }}\left( {a,b,c} \right){\text{ with radius }}r,{\text{ then}} \cr & {x^2} + {\left( {y - 7} \right)^2} + {z^2} = {\left( 6 \right)^2} \cr & {\text{Is a sphere centered at }}\left( {0,7,0} \right){\text{ with radius }}6 \cr & {\text{Then, }}{x^2} + {\left( {y - 7} \right)^2} + {z^2} \leqslant {\left( 6 \right)^2}{\text{ represents}} \cr & {\text{All the points on or inside the sphere centered at }}\left( {0,7,0} \right) \cr & {\text{with radius 6}} \cr} $$
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