Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 11 - Vectors and Vector-Valued Functions - 11.2 Vectors in Three Dimensions - 11.2 Exercises - Page 777: 5

Answer

$\textbf{u}+ \textbf{v}= <9,0,-6>$ $3\textbf{u}-\textbf{v}= <3,20,-22>$

Work Step by Step

$\textbf{u}+ \textbf{v}=<3+6,5+(-5),-7+1>$ = $<9,0,-6>$ $3\textbf{u}-\textbf{v}$=$<3\times3-6, 3\times5-(-5), 3\times(-7)-1>$ $= <3,20,-22>$
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