Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 11 - Vectors and Vector-Valued Functions - 11.1 Vectors in the Plane - 11.1 Exercises - Page 768: 45

Answer

$\left(\dfrac{6\sqrt{61}}{61},\dfrac{5\sqrt{61}}{61}\right)$ $\left(-\dfrac{6\sqrt{61}}{61},-\dfrac{5\sqrt{61}}{61}\right)$

Work Step by Step

We are given the points: $P(-4,1)$ $Q(3,-4)$ $R(2,6)$ Find the unit vector $\overrightarrow{u}$ with the same direction as $\overrightarrow{PR}$: $\overrightarrow{u}=\dfrac{\overrightarrow{PR}}{|\overrightarrow{PR}|}=\dfrac{(2-(-4),6-1)}{\sqrt{[2-(-4)]^2+(6-1)^2}}=\dfrac{(6,5)}{\sqrt{61}}=\left(\dfrac{6}{\sqrt{61}},\dfrac{5}{\sqrt{61}}\right)=\left(\dfrac{6\sqrt{61}}{61},\dfrac{5\sqrt{61}}{61}\right)$ Another unit vector parallel to $\overrightarrow{PR}$ is: $-\overrightarrow{u}=\left(-\dfrac{6\sqrt{61}}{61},-\dfrac{5\sqrt{61}}{61}\right)$
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