Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 11 - Vectors and Vector-Valued Functions - 11.1 Vectors in the Plane - 11.1 Exercises - Page 768: 44

Answer

$\left(-\dfrac{\sqrt{101}}{101},\dfrac{10\sqrt{101}}{101}\right)$

Work Step by Step

We are given the points: $P(-4,1)$ $Q(3,-4)$ $R(2,6)$ Find the unit vector with the same direction as $\overrightarrow{QR}$: $\dfrac{\overrightarrow{QR}}{|\overrightarrow{QR}|}=\dfrac{(2-3,6-(-4))}{\sqrt{(2-3)^2+[6-(-4)]^2}}=\dfrac{(-1,10)}{\sqrt{101}}=\left(-\dfrac{1}{\sqrt{101}},\dfrac{10}{\sqrt{101}}\right)=\left(-\dfrac{\sqrt{101}}{101},\dfrac{10\sqrt{101}}{101}\right)$
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