Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 11 - Vectors and Vector-Valued Functions - 11.1 Vectors in the Plane - 11.1 Exercises - Page 768: 27

Answer

$\overrightarrow{QT}$

Work Step by Step

We are given the points: P(−3,−1) Q(−1,2) R(1,2) S(3,5) T(4,2) U(6,4) Determine $\overrightarrow{QT},\overrightarrow{SU}$: $\overrightarrow{QT}(4-(-1),2-2)=(5,0)$ $\overrightarrow{SU}(6-3,4-5)=(3,-1)$ This means that $\overrightarrow{QT}=(5,0)$
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