Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 1 - Functions - 1.4 Trigonometric Functions and Their Inverse - 1.4 Exercises - Page 48: 9

Answer

The sine function is not one-to-one over its whole domain

Work Step by Step

The function $f(x)=\sin x$ is not an one-to-one function over its whole domain, therefore in order for the function to have an inverse we must restrict the domain so that the function is one-to-one. For example the domain might be $\left[-\dfrac{\pi}{2},\dfrac{\pi}{2}\right]$.
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