Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 1 - Functions - 1.4 Trigonometric Functions and Their Inverse - 1.4 Exercises - Page 48: 6

Answer

\[cscx = \frac{1}{{\sin x}}\,\,,\,secx = \frac{1}{{\cos x}}\,\,,\,\,\tan x = \frac{{\sin x}}{{\cos x}}\,\,,\,\cot x = \frac{{\cos x}}{{\sin x}}\]

Work Step by Step

\[\begin{gathered} \operatorname{Csc} \,x\,is\,the\,reciprocal\,ratio\,to\,\sin x. \hfill \\ \hfill \\ cscx = \frac{1}{{\sin x}} \hfill \\ \hfill \\ \sec \,x\,is\,the\,\,\,reciprocal\,ratio\,to\,\,\cos \,x. \hfill \\ \hfill \\ secx = \frac{1}{{\cos x}} \hfill \\ \hfill \\ \tan x\,\,\,is\,the\,\,ratio\,of\,\sin x\,to\,\cos x. \hfill \\ \hfill \\ \tan x = \frac{{\sin x}}{{\cos x}} \hfill \\ \hfill \\ \cot \,x\,is\,the\,reciprocal\,ratio\,to\,\tan \,x. \hfill \\ \hfill \\ \cot x = \frac{{\cos x}}{{\sin x}} \hfill \\ \end{gathered} \]
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