Answer
$\textbf{See Step By Step for Proof.}$
Work Step by Step
$\frac{sin(\theta)}{csc(\theta)} +\frac{cos(\theta)}{sec(\theta)} =1$
$csc(\theta) = \frac{1}{sin(\theta)}$ and $\sec(\theta) = \frac{1}{cos(\theta)}$, which we can substitute in.
$\dfrac{sin(\theta)}{1/sin(\theta)}+\dfrac{cos(\theta)}{1/cos(\theta)} = 1$
$sin^2(\theta)+cos^2(\theta) =1$
$1=1$
