Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 1 - Functions - 1.3 Inverse, Exponential, and Logarithmic Functions - 1.3 Exercises: 52

Answer

$2.62$

Work Step by Step

$\log_{b}\frac{b^{2}x^{5/2}}{\sqrt y}$ $=\log_{b}{b^{2}x^{5/2}} - \log_{b}\sqrt y$ $ = \log_{b}b^{2} + \log_{b}x^{5/2} - \log_{b}\sqrt y$ $=2 + (5/2)\log_{b}x- (1/2)\log_{b}y$ $=2 + (5/2)(0.36) - (1/2)(0.56)$ $=2.62$
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