Answer
See graph
Work Step by Step
We are given the function:
$f(x)=\begin{cases}
-2x-1,\text{ if }x1
\end{cases}$
We graph $y=-2x-1$ for $x\in(-\infty,-1)$, then $y=1$ for $x\in [-1,1]$ and $y=2x-1$ for $x\in(1,\infty)$:
Calculus: Early Transcendentals (2nd Edition)
by Briggs, Bill L.; Cochran, Lyle; Gillett, Bernard
Published by
Pearson
ISBN 10:
0321947347
ISBN 13:
978-0-32194-734-5
Chapter 1 - Functions - 1.2 Representing Functions - 1.2 Exercises - Page 22: 27
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