Answer
$f(g(2))=2$
$g(f(-2)=-2$
Work Step by Step
We know that $g(2)=-2$ and $f(2)=f(-2)$ (because f is even):
$f(g(2)=f(-2))=f(2)=2$
$g(f(-2)=g(f(2))=g(2)=-2$
Calculus: Early Transcendentals (2nd Edition)
by Briggs, Bill L.; Cochran, Lyle; Gillett, Bernard
Published by
Pearson
ISBN 10:
0321947347
ISBN 13:
978-0-32194-734-5
Chapter 1 - Functions - 1.1 Review of Functions - 1.1 Exercises - Page 9: 7
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