Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Appendix A - Appendix A Exercises - Page 1157: 11

Answer

$$y = m\left( {x - 4} \right) - 2$$

Work Step by Step

$$\eqalign{ & {\text{We know the slope }}m{\text{ and the point }}\left( {4, - 2} \right) \cr & {\text{use the point - slope form of equation of a line }}y - {y_1} = m\left( {x - {x_1}} \right) \cr & {\text{from the point }}\left( {4, - 2} \right){\text{ we obtain }}{x_1} = 4{\text{ and }}{y_1} = - 2 \cr & {\text{then}} \cr & y - {y_1} = m\left( {x - {x_1}} \right) \cr & y - \left( { - 2} \right) = m\left( {x - 4} \right) \cr & {\text{simplifying}} \cr & y + 2 = m\left( {x - 4} \right) \cr & y = m\left( {x - 4} \right) - 2 \cr} $$
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