Answer
No
Work Step by Step
$\int^ {\infty}_{-\infty}\frac{\ln 3}{t}dt =\int^ {3}_{1}\frac{\ln 3}{t}dt = (\ln(3))^2=1.207..\ne1$
Calculus Concepts: An Informal Approach to the Mathematics of Change 5th Edition
by LaTorre, Donald R.; Kenelly, John W.; Reed, Iris B.; Carpenter, Laurel R.; Harris, Cynthia R.
Published by
Brooks Cole
ISBN 10:
1-43904-957-2
ISBN 13:
978-1-43904-957-0
Chapter 6 - Analyzing Accumulated Change: Integrals in Action - 6.5 Activities - Page 474: 23
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